20x/(8x^2-4x)

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Solution for 20x/(8x^2-4x) equation: 


D( x )

8*x^2-(4*x) = 0

8*x^2-(4*x) = 0

8*x^2-(4*x) = 0

8*x^2-4*x = 0

8*x^2-4*x = 0

DELTA = (-4)^2-(0*4*8)

DELTA = 16

DELTA > 0

x = (16^(1/2)+4)/(2*8) or x = (4-16^(1/2))/(2*8)

x = 1/2 or x = 0

x in (-oo:0) U (0:1/2) U (1/2:+oo)

(20*x)/(8*x^2-(4*x)) = 0

(20*x)/(8*x^2-4*x) = 0

8*x^2-4*x = 0

4*x*(2*x-1) = 0

2*x-1 = 0 // + 1

2*x = 1 // : 2

x = 1/2

4*x*(x-1/2) = 0

(20*x)/(4*x*(x-1/2)) = 0

20*x = 0 // : 20

x = 0

x in { 0} 

x belongs to the empty set

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